Question

Area = 1x 10-8 m2
Example 2 : A weight exerts force of 100 N on a steel wire of cross-sectional area
0.02 cm. Find extension produced if the length of wire is 5 m. (Y = 2 x 1011 N/m2)
IS. - 2002 - 2 M)​

Answer 1

Answer:

hopefully it will work ☺️☺️☺️

Answer 2

Answer:

$1.5 \times 10^{-5} \mathrm{~m}$

Explanation:

Exerted weight = exerted force=$F=120 \mathrm{~N}$

cross-sectional area =$A \cdot 20 \mathrm{An}$

$=0.02 \mathrm{~cm}^{2}$

$=0.02 \times 10^{-4} \mathrm{~m}^{2}$

Length of the wire $=L=5 \mathrm{~m}$.

Young's modulus for this metal $=2 \times 10^{13} \mathrm{~N} / \mathrm{m}^{2}$

$\therefore$ length extended:

$Y =\frac{F / A}{\Delta V / L}$

$\Rightarrow Y=\frac{F \times L}{A \times \Delta L}$

$\Rightarrow \Delta L=\frac{F \times L}{A \times Y}=\frac{120 \times 5}{0.02 \times 10^{-4} \times 2 \times 10^{13} \mathrm{~m}}$

$=1.5 \times 10^{-5} \mathrm{~m}$

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