area 352cm2 and radius 12cm find the central angle of a sector
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Area of sector = ø / 360 × πr^2
352 = ø /360 × πr^2
(352 ×360 × 7)/(22×12×12) = ø
280° = ø
Angle of sector is 280°
Plz put in brainlist
352 = ø /360 × πr^2
(352 ×360 × 7)/(22×12×12) = ø
280° = ø
Angle of sector is 280°
Plz put in brainlist
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