Question

area
4. Find the
of a triangle two sides
of which are 18 cm and 10 cm and the
perimeter is 42 cm.
Acm
​

Answer 1

Answer:

69.64cm^2

Step-by-step explanation:

perimeter of a triangle = sum of all sides

perimeter is given = 42 cm

let the third side be x

according to question,

18 + 10 + x = 42 cm

x = 14 cm

Now, applying heron's formula,

s = a +b +c/2

s = 21

√s(s - a) (s- b) (s - c)

√21 ( 21 - 18)(21-10)(21-14)

69.64cm^2

Answer 2

Answer:

here is your answer write from it