Math, asked by chaudharyrinu40, 10 months ago

area =468 cm2 d1= ? d2=26 m find the missing value of rombus​

Answers

Answered by pandaXop
11

Missing value = 36 cm

Step-by-step explanation:

Correct Question: Area should be in if one diagonal is in meter or if area is given in cm² then diagonal should be also in cm.

Given:

  • Area of rhombus is 468 cm².
  • Measure of second diagonal of rhombus is 26 cm.

To Find:

  • What is the measure of first diagonal of rhombus ?

Solution: Let the first diagonal of rhombus be x cm.

As we know that the :-

Area of Rhombus = 1/2\times (D¹) \times ()

A/q

  • Area of rhombus = 468 cm²

\implies{\rm } 468 = 1/2 \times () \times ()

\implies{\rm } 468 = 1/2 \times (x) \times 26

\implies{\rm } 468 = 13 \times (x)

\implies{\rm } 468 = 13x

\implies{\rm } 468/13 = x

\implies{\rm } 36 cm = x

Hence, the measure of first diagonal i.e d¹ is x = 36 cm.

_____________________

★ Verification ★

➟ 1/2 \times\times d² = 468 cm²

➟ 1/2 \times 36 \times 26 = 468 cm²

➟ 18 \times 26 = 468 cm²

➟ 468 cm² = 468 cm²

[ Verified ]

Rhombus is type of quadrilateral or parallelogram.

All 4 sides of rhombus are equal.

Perimeter of rhombus = 4(Side)

Diagonals bisect each other at 90°.

Opposite sides are parallel.

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