Question

Area = 56 dm2 base = 2.8 m

Answer 1

Answer:

Base of triangle = 2.8 m

1 m = 10 dm

2.8 m = 28 dm

So, Base of triangle = 2.8 m

Area of triangle =\frac{1}{2} \times Base \times Height

2

1

×Base×Height

Area of triangle =\frac{1}{2} \times 28 \times Height

2

1

×28×Height

We are given that area of triangle is 56 dM square

So, \frac{1}{2} \times 28 \times Height = 56

2

1

×28×Height=56

Height =\frac{56 \times 2}{2 \times 28}

2×28

56×2

Height = 2

Hence the height of the triangle is 2 dm

#Learn more:

Find the height of the triangle whose:

(i) area = 28.9 m², base = 8.5 m

(ii) area = 56 dm², base = 2.8 m

https://brainly.in/question/6004094

Answer 2

Step-by-step explanation:

H=56/28

= 2.......…

...............m