area and perimeter find both
Answers
Answer:
Area of rectangle =lxb
, 28x16
==448
Peimeter of rectangle =2(l+b)
=2x34
, 68
Area Of Figure = 448 cm²
Perimeter Of Figure = 119.92 cm
Step-by-step explanation:
GIVEN
Length = 28 cm
Breadth = 16 cm
Radius = Diameter / 2 = 28 / 2 = 14 cm
___________________________
TO FIND
Area of figure and Perimeter of figure
___________________________
Area Of Rectangle = Length × Breadth
Area Of Rectangle = 28 × 16
Area Of Rectangle = 448
Area Of Rectangle = 448 cm
___________________________
Area Of Semicircle = ½ ( π × r² )
Area Of Semicircle = ½ × ( 3.14 × 14² )
Area Of Semicircle = ½ × 615.44
Area Of Semicircle = 307.72
Area Of Semicircle = 307.72 cm
___________________________
Area Of Figure = ( Area Of Rectangle - Area Of Semicircle ) + Area Of Semicircle
Area Of Figure = ( 448 - 307.72 ) + 307.72
Area Of Figure = 140.28 + 307.72
Area Of Figure = 448
Area Of Figure = 448 cm²
___________________________
Now let's find the perimeter of a figure
We know that,
Perimeter Of Rectangle = 2 × ( Length + Breadth )
Perimeter Of Rectangle = 2 × ( 28 + 16 )
Perimeter Of Rectangle = 2 × 44
Perimeter Of Rectangle = 88
Perimeter Of Rectangle = 88 cm
___________________________
We know that,
Perimeter Of Semicircle = ½ × ( π × d ) + d
Perimeter Of Semicircle = ½ × ( 3.14 × 28 ) + 28
Perimeter Of Semicircle = ½ × 87.92 + 28
Perimeter Of Semicircle = 43.96 + 28
Perimeter Of Semicircle = 71.96
Perimeter Of Semicircle = 71.96 cm
___________________________
Perimeter Of Figure = ( 2 × breadth ) + ( 2 × ( Perimeter Of Semicircle - Diameter ) )
Perimeter Of Figure = 2 × 16 + 2 × ( 71.96 - 28 )
Perimeter Of Figure = ( 2 × 16 ) + ( 2 × 43.96 )
Perimeter Of Figure = 32 + 87.92
Perimeter Of Figure = 119.92