Area and perimeter of a rectangular park are 600 sq. m and 100 m respectively find the leng th and breadth of a park by quadratic equations
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Answered by
2
Answer:
Step-by-step explanation:
Let length be l and breadth be b
ATQ
2{l + b} = 100
l + b = 50
L = 50 - b
L * B = 600
50b - b² = 600
b² - 50 b + 600 = 0
b² - 30b - 20b + 600 = 0
B{B - 30} - 20{B - 30} = 0
{B - 30}{B - 20} = 0
B = 20 and not 30 as L is always greater than breadth
L = 30
Answered by
0
Answer:
Let length be l and breadth be b
ATQ
2{l + b} = 100
l + b = 50
L = 50 - b
L * B = 600
50b - b² = 600
b² - 50 b + 600 = 0
b² - 30b - 20b + 600 = 0
B{B - 30} - 20{B - 30} = 0
{B - 30}{B - 20} = 0
B = 20 and not 30 as L is always greater than breadth
L = 30
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