Math, asked by navneetkhare16, 1 year ago

Area bounded by the curve y = xsinx and x-axis between x=0 and x=2

Answers

Answered by kvnmurty
1
area =  \int\limits^2_0 {x\ Sin\ x} \, dx =[-x\ Cos\ x+sin\ x]_0^2\\\\= |- 2\ Cos\ 2+Sin\ 2 |
= 1.7416  nearly = √3

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