Area if square increase by 69% find sides % increased by?
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Let the original area be A, and let the side of the original square be ll
therefore:
AA = l2l2
If the area increased by 69%, this means our new area is
(1+0.69)A(1+0.69)A that is (1.69)A(1.69)A
Let the new side be xx, therefore:
x2=1.69Ax2=1.69A
and because:
A=l2A=l2:
therefore:
x2=1.69l2x2=1.69l2
Taking the square root of both sides we get:
x=1.3lx=1.3l
x=(1+0.3)lx=(1+0.3)l
Therefore the increase in length is 0.3l0.3l or 3030of the original length.
therefore:
AA = l2l2
If the area increased by 69%, this means our new area is
(1+0.69)A(1+0.69)A that is (1.69)A(1.69)A
Let the new side be xx, therefore:
x2=1.69Ax2=1.69A
and because:
A=l2A=l2:
therefore:
x2=1.69l2x2=1.69l2
Taking the square root of both sides we get:
x=1.3lx=1.3l
x=(1+0.3)lx=(1+0.3)l
Therefore the increase in length is 0.3l0.3l or 3030of the original length.
Answered by
1
30%.
let the area of sqr be 100 and now it increases to 169 so side is increased by 3 means 30%
let the area of sqr be 100 and now it increases to 169 so side is increased by 3 means 30%
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