area in first quadrant between the ellipse X^2 +2Y^2 =a^2 and 2X^2+ Y^2 =a ^2
Answers
Answered by
0
Answer:
Step-by-step explanation:
He splits the region into two parts using the intervals [0,a/3–√] and [a/3–√,a/2–√] , each having its own function.
An alternative would be to consider:
8(∫a/3√0((a2−x2)/2−−−−−−−−−√−x)dx)
The answer, expressed in a is:
22–√arcsin(1/3–√)a2
Similar questions