Question

Area in of 11m 298 badge =8cm height =?​

Answer 1

Answer:

In ∆ABC ,AD is median . D. will be the mid point of BC.

BD=CD= BC/2= 14/2=7cms.

AB^2+AC^2 =2(AD^2+BD^2)

8^2+10^2=2(AD^2+7^2)

164/2=AD^2+49

82–49=AD^2

33=AD^2

AD=√33 cms.

We know that centroid (G ) lies on median AD and G divides the median

in the ratio of 2 : 1 .

Therefore. AG. =2/3.AD = (2.√33)/3 cms =(2×5.74)/3 cms.

= ( 11.48)/3 = 3.83 cms. Answer.