Question

Area moment of inertia of a semicircle about its centroid

Answer 1

Answer:

Step-by-step explanation:

Centroid, Area, Moments of Inertia, Polar Moments of Inertia, & Radius of Gyration of a Semi-Circular Cross-Section. ... Moment of Inertia about the x axis. Ix · Moment of Inertia about the y axis. Iy · Polar Moment of Inertia about the z axis. Jz.

Answer 2

# Given-

m = 1.7×10-27 kg

r = 4×10^-10 m

# Solution-

Here,

Total mass M = 2m

Radius of rotation R = r/2

Moment of inertia of hydrogen molecule is given by-

M.I. = MR^2

M.I. = (2m)(r/2)^2

M.I. = mr^2/2

M.I. = 1.7×10-27 × (4×10^-10)^2 / 2

M.I. = 1.36×10^-46 kgm^2