Question

Area od triangle of vertices (2,0) (1,3) (0,1)

Answer 1

$\LARGE\underline{\bf Area \:of\: triangle :} \\ \\ \tt\longrightarrow Area= \frac{1}{2}\bigg [ x_1(y_2 - y_3) + x_2(y_3 -y_1) + x_3(y_1 - y_2)\bigg] \\ \\\tt\longrightarrow Area = \frac{1}{2}\bigg[2(3 - 1) + 1(1 - 0) + 0(0 - 3)\bigg] \\ \\\tt\longrightarrow Area = \frac{1}{2}\bigg[2(2) + 1(1) + 0( - 3)\bigg] \\ \\\tt\longrightarrow Area = \frac{1}{2}\bigg[4 + 1 + 0\bigg] \\ \\\tt\longrightarrow Area = \frac{1}{2} \times 5 \\ \\\tt\longrightarrow Area = \frac{5}{2} \\ \\\tt\longrightarrow Area = 2.5 \: {unit}^{2}$