Question

Area of a circle in which a chord of length root 2 makes an angle pi/2 at the centre is

Answer 1

it can be solved by easily through trigo

Answer 2

Answer:

$\text{Area of circle=}\frac{22}{7} units^2$

Step-by-step explanation:

Given a chord of length $\sqrt2$ makes an angle $\frac{\pi}{2}$ at the centre

we have to find the area of circle.

In ΔOAB, by Pythagoras theorem

$x^2+x^2=(\sqrt2)^2$

$2x^2=2$

$x=1$

The radius is 1 units

$\text{Area of circle=}\pi r^2$

$=\frac{22}{7}\times 1^2=\frac{22}{7} units^2$