Area of a circle inscribed in an equilateral triangle is 154 sq cm . find the perimeter of the triangle
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The area of the circle =154cm² and area =πr²
154 = 22/7 × r²
154 × 7/22=r²
49=r²
r =7cm
Let the triangle be ABC the equilateral triangle then AD the altitude =height.
The angle bisectors equal to the altitudes and medians whose point of intersection divide the medians in the ratio 2:1
Let center of circle =O then OD =1/3AD
r=h/3
7=h/3
h=3× 7=21cm
Let each side of the triangle be x then the altitude of the equilateral triangle is √3/2 times its side by Pythagoras theorem.
h=√3x/2
x=2h/√3
(2×21)/√3
42/1.7321=24.2480
x=24.2480cm
Perimeter =24.2480 × 3=72.744cm
154 = 22/7 × r²
154 × 7/22=r²
49=r²
r =7cm
Let the triangle be ABC the equilateral triangle then AD the altitude =height.
The angle bisectors equal to the altitudes and medians whose point of intersection divide the medians in the ratio 2:1
Let center of circle =O then OD =1/3AD
r=h/3
7=h/3
h=3× 7=21cm
Let each side of the triangle be x then the altitude of the equilateral triangle is √3/2 times its side by Pythagoras theorem.
h=√3x/2
x=2h/√3
(2×21)/√3
42/1.7321=24.2480
x=24.2480cm
Perimeter =24.2480 × 3=72.744cm
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