Math, asked by ridam123456789000000, 1 year ago

area of a circle is πx^2+6πx+9π. find radius

Answers

Answered by abhi569
7
We know,

Area of circle = πr²

πx² + 6πx + 9π = πr²

π(x² + 6x + 9) = πr²

x² + 6x + 9 = r²

x² + 3x + 3x + 9 = r²

x(x + 3) + 3(x + 3) = r²

(x + 3)(x + 3) = r²

(x + 3)² = r²

x + 3 = radius




I hope this will help you


(-:
Answered by Cutiepie93
8
Hello friends!!

Here is your answer :

We know that,

Area of circle

 = \pi {r}^{2}

Given,

area = \pi {x}^{2}  + 6\pi  x + 9\pi


According to question,


\pi {x}^{2}  + 6\pi  x + 9\pi = \pi { r}^{2}


\pi( {x}^{2}  + 6x + 9) = \pi {r}^{2}


 {x}^{2}  + 6x + 9 =  \frac{\pi {r}^{2} }{\pi}

 {(x)}^{2}  + 2(x)(3) +  {(3)}^{2}  =  {r}^{2}


Using identity :

( a + b )² = a² + 2ab + b²


 {(x + 3)}^{2}  =  {r}^{2}

r = x + 3



Therefore, Radius of circle = x + 3

Hope it helps you.. ^_^

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