area of a parallelogram ABCD is

. If AB = 15cm , then find the distance between AB and DC. IF angle CDA = 150°, find the perimeter of the parallelogram.
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Step-by-step explanation:
Given that, ABCD is a parallelogram such that AB = 15 cm and CDA = 150°.
We know, in a parallelogram, sum of adjacent angles is 180°.
So,
Let from D, draw DE perpendicular to AB intersecting AB at E.
So, Distance between AB and CD is DE.
Given that,
So, Distance between AB and CD is 8 cm.
Now, In right-angle triangle ADE
On substituting the value of sin30° and DE, we get
Now,
Hence,
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