Question

Area of a parallelogram pqrs is at 120 CM square and PQ is equal to 10 cm, PS is equal to 15 CM, PT is perpendicular to QR. find the length of 1. PT and 2. QT

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Answer 1

Area of parallelogram =120 cm

2

=15×PM

⟹PM=8 cm

Now in △PMS

PS

2

=SM

2

+PM

2

10

2

=SM

2

+8

2

⟹SM=10

2

−8

2

=6 cm