Question

Area of a quadrant of a circle whose circumferencecis 44 cm

Answer 1

Circumference = 44cm

=> 2πR = 44

=> πR = 22

=> R = $\frac{22 × 7}{22}$ = 7cm

We know that, Angle of a quadrant = 90°

Area of a quadrant = $\frac{90}{360} × πR^2$

= $\frac{1}{4} × \frac{22}{7} × (7)^2$

= $\frac{11 × 7}{2}$

= $\frac{77}{2}$

= $\fbox{38.5 cm^2}$

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