Question

area of a quadrilateral ABCD is 20 CM square and perpendicular on BD from opposite vertices are 1 cm and 1.5 CM the length of BD is

Answer 1

Answer:

The length of BD is 16 cm

Step-by-step explanation:

Given area of a quadrilateral ABCD is $20cm^2$ and perpendicular on BD from opposite vertices are 1 cm and 1.5 cm.we have to find the length of BD.

area of quadrilateral ABCD = ar(ΔABD)+ar(ΔBCD)

                                              $(\frac{1}{2}\times base BD\times height AO)+(\frac{1}{2}\times base BD\times height CO)$

                                             = $(\frac{1}{2}\times BD\times 1.5)+(\frac{1}{2}\times base BD\times 1)$

                                             = $\frac{1}{2}\times BD(1.5+1)$

                                             = $\frac{1}{2}\times BD\times 2.5$

But the area of quadrilateral is  $20cm^2$

⇒$\frac{1}{2}\times BD\times 2.5=20cm^2$

⇒ BD=16 cm

Answer 2

Answer:

The length of BD is 16 cm

Step-by-step explanation:

Given area of a quadrilateral ABCD is  and perpendicular on BD from opposite vertices are 1 cm and 1.5 cm.we have to find the length of BD.

area of quadrilateral ABCD = ar(ΔABD)+ar(ΔBCD)

But the area of quadrilateral is   BD=16 cm