Question

Area of a rectangle is 21 cm2. If length of the rectangle is 3 cm, find the perimeter of the rectangle.

Answer 1

According to the Question

It is given that,

• Area of Rectangle = 21 cm²
• Length = 3cm

we have to calculate the perimeter of the rectangle .

Firstly we calculate the breadth of rectangle .

• Area of Rectangle = Length × Breadth

On substituting the value we get

↠ 21 = 3 × breadth

↠ 21/3 = breadth

↠7 cm = breadth

Now, calculating the perimeter of rectangle .

Perimeter of Rectangle = 2(length+breadth)

On substituting the value we get

↠ Perimeter of Rectangle = 2(3+7)

↠ Perimeter of Rectangle = 2 ( 10)

↠ Perimeter of Rectangle = 20cm

• Hence, the perimeter of the rectangle is 20cm .

Additional Information !!

$\begin{gathered}\boxed{\begin {array}{cc}\\ \quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

Answer 2

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