Question

area of a rectangle is 24 sq.m and premetre 20 cm.then length of diagonal is

Answer 1

Answer:

Step-by-step explanation:

l*b=24

2(l+b)=20

therefore,

l+b=10

therefore l=10-b

(l+b)^2=100

l^2+b^2+2lb=100

l^2+b^2+48=100

l^2+B^2=100-48=52

as l=10-b

therefore

(10-b)^2+b^2=52

100+b^2- 20b+b^2=52

2b^2 - 20b +100-52=0

2b^2-20b+48=0

by factorization method

b=6 or b=4

if b=6

l=10-b=10-6=4

and if b=4

l=10-b=10-4=6

cosider l=4 and b=6

diagonal^2= 4^2+ 6^2

d^2=16+36=52

d=2$\sqrt{13$