Question

Area of a rectangle is 40cm², if it's length is 20cm and it's breadth is 2cm, find the area if it's length is doubled and it's breadth is thrice. ​

Answer 1

➣ AnSwer :-

Doubled length of the rectangle :- 20×2 = 40 cm

Thribbled breadth of the rectangle :- 2×3 = 6 cm

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Area of the rectangle :-

$\large{\orange {\bf {\underline {\underline {Length×Breadth}}}}}$

$\longrightarrow \sf \:40 \times 6 \: cm$

$\longrightarrow \sf {240}^{2}$

Therefore,the area of the rectangle is 240 cm².

Answer 2

Answer:

240$cm^{2}$

Step-by-step explanation:

Area of rectangle = $40cm^{2}$

Length₁ =20cm

Breadth₁ = 2cm

according to the question ,

Length₂ = 2(20) = 40 cm

Breadth₂ = 3(2) = 6 cm

Therefore ,

area of new rectangle =  ( 40* 6 ) $cm^{2}$ = 240$cm^{2}$