Math, asked by souradeep66041, 15 days ago

Area of a rectangle is 600cmsq. Breadth 20cm then find its perimeter

Answers

Answered by Yuseong
3

Step-by-step explanation:

As per the provided information in the given question, we have :

  • Area of rectangle = 600 cm²
  • Breadth = 20 cm

We are asked to calculate the perimeter of the rectangle.

In order to calculate the the perimeter of the rectangle, firstly we need to find its length. In order to calculate that so, we'll be using the formula of area of the rectangle as a linear equation, and then by using transposition method, we'll find the value of the unknown value.

Let the length of the rectangle be l. According to the question,

  \longrightarrow \sf{\quad { Area_{(Rectangle)} = Length \times Breadth}} \\

Substitute the known values we have been provided in the question.

  \longrightarrow \sf{\quad { 600 \; cm^2= \ell \times 20 \; cm}} \\

Transpose 20 cm from RHS to LHS, it's arithmetic operator will get changed.

  \longrightarrow \sf{\quad { \cancel{\dfrac{600 \; cm^2}{20\; cm}}= \ell}} \\

Dividing 600 by 20.

  \longrightarrow \quad {\textbf{\textsf{ 30 \; cm = \; }} \ell }\\

 \underline{ \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad} \\

Now, let's find out the perimeter. Let the perimeter be P.

  \longrightarrow \sf{\quad { P_{(Rectangle)} = 2(Length + Breadth)}} \\

Substitute the values we have.

  \longrightarrow \sf{\quad { P= 2(30\; cm + 20\; cm)}} \\

Performing addition of the terms in the brackets.

  \longrightarrow \sf{\quad { P= 2(50\; cm)}} \\

Performing multiplication in RHS.

  \longrightarrow \quad \underline{\boxed {\textbf{\textsf{ P = 100 \; cm }}}}\\

Therefore, the perimeter of the rectangle is 100 cm.

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