area of a rectangle is 630 square metre and its length is 35 M find the perimeter of the rectangle
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HEYA!!!!
Given,
area of rectangle = 630
length = 35
breadth = x
area of rectangle = l × b
630 = 35× x
630/35=x
x = 18
Therefore, breadth is 18..
then perimeter of rectangle = 2 ( l+b )
= 2 ( 35+18)
= 2 ( 53)
= 106m
HOPE THIS HELPS U @MP #MAHABOOBPASHA #☺☺
Given,
area of rectangle = 630
length = 35
breadth = x
area of rectangle = l × b
630 = 35× x
630/35=x
x = 18
Therefore, breadth is 18..
then perimeter of rectangle = 2 ( l+b )
= 2 ( 35+18)
= 2 ( 53)
= 106m
HOPE THIS HELPS U @MP #MAHABOOBPASHA #☺☺
Answered by
0
Area of rectangle =l*b
Let the breadth be x
35*x=630
X=630/35=18
Breadth =x=18m
Perimeter =2*(l+b)
=2*(35+18)
2*53=106m
Let the breadth be x
35*x=630
X=630/35=18
Breadth =x=18m
Perimeter =2*(l+b)
=2*(35+18)
2*53=106m
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