Question

Area of a rectangle of length '6a' units and breadth ' 7b' units is what in sq.units.​

Answer 1

Answer:

Answer

Length of rectangle is reduced by 5 units and

its breadth is increased by 3 units and the

area of rectangle is reduced by 8 sq. units

(L−5)(W+3)=LW−8

LW+3L−5W−15=LW−8

3L−5W=7 __(1)

Length is reduced by 3 units and breadth is increased

by 2 units, then the area of Rectangle will be

67 sq. units increased

(L−3)(W+2)=LW+67

LW+2L−3W−6=LW+67

2L−3W=73 __(2)

Solving (1)×2 by (2)×3

2(3L−5W=7)→6L−10W=14

3(2L−3W=73)→6L−9W=219

−W=−205

W=205

W = 205 in eq (1).

3L−5(205)=7

3L=7+1025

3L=1032→L=

3

1032

L=344