Question

area of a rectangle park is 3600sq.m its breadht is 60cm. find its lenght and perimeter​

Answer 1

Answer:

$\bigstar{\bold{Length\:of\:the\:rectangle=6000\:m}}$

$\bigstar{\bold{Perimeter=12001.1\:m}}$

Step-by-step explanation:

$\Large{\underline{\bf{Given:}}}$

• Area of the park = 3600 m²
• Breadth of the rectangle = 60 cm = 0.6 m

$\Large{\underline{\bf{To\:Find:}}}$

• Length of the rectangular park
• Perimeter of the rectangular park

$\Large{\underline{\bf{Solution:}}}$

➛ First we have to find the length of the rectangular park.

➛ We know that area of a rectangle is given by,

   Area of rectangle = breadth × length

➛ Substitute the data,

    3600 = 60 × length

    Length = 3600/0.6

    Length = 6000 m

➛ Hence length of the rectangle is 6000 m.

   $\boxed{\bold{Length\:of\:the\:rectangle=6000\:m}}$

➛ Now we have to find the perimeter of the rectangle.

➛ We know that,

   Perimeter = 2 (l + b)

    where l is the length of the rectangle

    b is the breadth of the rectangle

➛ Substitute the data,

    Perimeter = 2 (6000 + 0.6)

    Perimeter =  2 × 6000.6

    Perimeter = 12001.2 m

➛ Hence the perimeter of the rectangle is 12001.2 m.

   $\boxed{\bold{Perimeter=12001.1\:m}}$

$\Large{\underline{\bf{Notes:}}}$

➛ Area of rectangle = Length × Breadth

➛ Perimeter of a rectangle 2 (length + breadth)

Answer 2

♣ Qᴜᴇꜱᴛɪᴏɴ :

• Area of a rectangular park is 3600 m², it's breadth is 60 cm .Find its length and perimeter​

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large Length}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 0.6m }\put(-0.5,-0.4){\bf C}\put(-0.5,3.2){\bf A}\put(5.3,-0.4){\bf D}\put(5.3,3.2){\bf B}\end{picture}$

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♣ ᴀɴꜱᴡᴇʀ :

• Length = 6000 m

• Perimeter of Rectangle = 12001.2 m

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 6000 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 0.6m }\put(-0.5,-.4){\bf C}\put(-0.5,3.2){\bf A}\put(5.3,-0.4){\bf D}\put(5.3,3.2){\bf B}\end{picture}$

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♣ ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴꜱ :

Area of a rectangular park is 3600 m²

Area of Rectangle = Length × Breadth

Area of Rectangle = Length × 60 cm

Area of Rectangle = Length × 0.6 m

3600 m² = Length × 0.6 m

Multiply Both sides by 10

3600 m² × 10 = Length × 0.6 m × 10

36000 m² =  Length × 6 m

Divide both sides by 6 m

(36000 m²)/6 m =  (Length × 6 m)/6 m

6000 m = Length

Switch Sides

Length = 6000 m

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 6000 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 0.6m }\put(-0.5,-0.4){\bf C}\put(-0.5,3.2){\bf A}\put(5.3,-0.4){\bf D}\put(5.3,3.2){\bf B}\end{picture}$

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Perimeter of Rectangle = 2 × (Length + Breadth)

We already have the values of Length and Breadth, Substitute the values

Perimeter of Rectangle = 2 × (6000 m + 0.6 m)

Perimeter of Rectangle = 2 × (6000.6)

Perimeter of Rectangle = 12001.2 m

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