area of a rectangle with length (4x-1)cm and width 2xcm is 10cm². Determine the:
a)Value of x b)Its length and width c)Its perimeter
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a) area of rectangle=l×b=10cm2
2x ×(4x-1) = 8x-2x=10cm2
8x-2x=10cm2
6x=10cm2
x=10/6
x=5/3
b)if x=5/3
length=(4x-1) width=2x
4×5/3-1 =2×5/3
20/3-3/3 =10/3
17/3
c)2(l+w)
2×(17/3+10/3)
2×9
18
2x ×(4x-1) = 8x-2x=10cm2
8x-2x=10cm2
6x=10cm2
x=10/6
x=5/3
b)if x=5/3
length=(4x-1) width=2x
4×5/3-1 =2×5/3
20/3-3/3 =10/3
17/3
c)2(l+w)
2×(17/3+10/3)
2×9
18
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