Question

Area of a rectangular field is 10 whole 1/2msquare.If the length of the field is 2 whole 2/4m,find breadth
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Answer 1

Step-by-step explanation:

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Answer 2

Question :-

Area of a rectangular field is $\tt{ 10 \dfrac{1}{2}}$ sqmeters . If the length of the field is $\tt{2 \dfrac{2}{4}}$ meters . Find the breadth ?

Answer :-

Given :-

Area of the rectangular field = $\tt{ 10 \dfrac{1}{2}}$ sq. meters

Length of the field = $\tt{2 \dfrac{2}{4}}$ meters

Required to find :-

Breadth of the rectangular field

Formula used :-

$\large{\boxed{\rm{Area \;of \;a \;rectangular\; field \;= length \times breadth}}}$

Solution :-

Given :-

Area of the rectangular field = $\tt{ 10 \dfrac{1}{2}}$ sq.meters

Length of the rectangular field = $\tt{2 \dfrac{2}{4}}$ meters

He asked us to find the breadth of the field .

So,

In order to find the breadth of the field

Let's convert the mixed fractions into improper fractions .

Hence,

Area of the rectangular field = $\tt{ 10 \dfrac{1}{2}}$ = 21/2 meters

Length of the rectangular field = $\tt{2 \dfrac{2}{4}}$ = 10/4 meters

Similarly,

Let the breadth of the rectangular field be " x " meters .

Using the formula ,

$\large{\boxed{\rm{Area \;of \;a \;rectangular\; field \;= length \times breadth}}}$

According to the problem,

length x breadth = Area

So,

$\longrightarrow{\tt{ \dfrac{10}{4} \times x = \dfrac{21}{2}}}$

$\longrightarrow{\tt{ \dfrac{10}{4}x = \dfrac{21}{2}}}$

$\longrightarrow{\tt{ x = \dfrac{ \dfrac{21}{2}}{ \dfrac{10}{4}}}}$

$\Rightarrow{\tt{ x = \dfrac{ 21 }{2} \div \dfrac{10}{4}}}$

$\Rightarrow{\tt{ x = \dfrac{21}{2} \times \dfrac{4}{10}}}$

$\Rightarrow{\tt{ x = 21 \times \dfrac{2}{10}}}$

$\Rightarrow{\tt{ x = \dfrac{21 \times 2}{10}}}$

$\Rightarrow{\tt{ x = \dfrac{21}{5}}}$

This can be written as

$\leadsto{\tt{ x = 4 \dfrac{1}{5}}}$

$\large{\underline{\leadsto{\boxed{\therefore{ Breadth = 4 \dfrac{1}{5}}}}}}$

Points to remember :-

• Area of the rectangle = length x breadth

• Perimeter of the rectangle = 2(length + breadth )

• In a rectangle, opposite side are equal

( Refer to the attachment )