Math, asked by khushiaiks, 1 year ago

area of a rectangular field whose length is twice its breadth is 4050 cm square A man cycles along the boundary of field at 45 cm per second find the time taken by him to return to the starting point

Answers

Answered by santy2
1

Let the breadth of the rectangle be x.

The length is 2x.

The area of a rectangle = Length × Width

The area = 2x × x = 2x²

This equals to 4050.

Equating the two we have :

2x² = 4050

x² = 4050/2

x² = 2025

x = √2025

x = 45 cm

The length is thus 45 × 2 = 90cm

When the man cycles around, he covers the perimeter of the field.

Perimeter = 2(W + L)

Perimeter = 2(90 + 45) = 2 × 135 = 270cm

Now :

Distance = 270 cm

Speed = 45 cm per second

Time = Distance / Speed

= 270/45 = 6

We have 6 seconds

Answered by Sidyandex
0

The breath of the rectangular field is B and the length is 2B

Area of the rectangular field = 4050 square cm

L * B = 4050

2B * B = 4050

B^2 = 4050/2 = 2025

B = square root of 2025 = 45 cm

Hence L = 2 * B = 2 * 45 = 90 cm

Speed of the cycle = 45 cm/sec

Perimeter of the field = 2 (L + B) = 2 (45 + 90) = 270 cm

Speed = distance/time

Time = distance/speed

Time = 270/45

Time = 6 sec

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