Area of a rectangular park is 100 square meter. Length of the park is 15 meter
more than the breadth. If someone wants to fence along the sides of the park and
cost of fencing one meter is Rs. 5, then find the total cost of fencing all sides of the
park.
Answers
Answer:
500
Step-by-step explanation:
l=b+15
area =l*b
100=b+15)*b
100=b^2+15b
b^2+15b-100=0
b=-15+-√225+400/2
b=-15+-25/2
b=10/2=5 other neglected as its negative
hence l=20m
hence area =20*5=100m^2
hence cost of fencing =100*5=500rupees
Let the breadth be x
then,
length be (x+15) meters
According to the Question
area of rectangle = 100 m²
(x)(x+15)=100
x²+15x=100
x²+15x-100=0
x²+20x-5x-100=0
x(x+20)-5(x+20)=0
(x+20)(x-5)=0
x+20=0 x-5=0
x= -20 or x =5
x=5 ( since measurement can not be negative)
breadth = 5m
length = x +15m = 20m
Now,
perimeter of the rectangle = l+b
= 25m
Cost of fencing at Rs. 5 per meter=25 ×5
= Rs. 125
Hope get help from this.