Math, asked by shubhdon9388, 1 year ago

Area of a rectangular plot is 528 m square the length of the plot is 1 m more than twice its breadth find the length and breadth of the plot.

Answers

Answered by Anonymous
9
QUESTION

Area of a rectangular plot is 528 m square the length of the plot is 1 m more than twice its breadth find the length and breadth of the plot.


ANSWER


GIVEN

Area of a rectangular plot =528 m square

Length of the plot is 1 m more than twice its breadth.

so , according to given condition

.
Let breathe of rectangular plot=x

so , length. of rectangular plot =(2x+1)



FIND

length and breadth




BACK ON QUESTION




FORMULA USED

area \: of \:  \: rectangular \: plot = l \times b

so put its value


x \times (2x + 1) = 528



 =2  {x}^{2}  + x = 528




 = 2 {x}^{2}  + x - 528 = 0



on solving this quadratic equations we get



 = 2 {x}^{2}   +  33x - 32x - 528



 = x(2x + 33) - 16(2x  +  33)



 = (x - 16) \:  \: and \:( 2x  + 33)




so, x=16 and X=-33/2


NOTE

length can never be negative value .

=> x=16m

so , Breadth=16m

=>
length. of rectangular plot =(2x+1)

=2(16)+1

=32+1

=33m
Answered by Anonymous
4

\rule{300}3

\Huge{\red{\underline{\textsf{Answer}}}}

Let breadth of a plot is x m.

  • According to the question,

\leadstoLength of plot = ( 2 × breadth ) + l

\leadsto( 2 × x × l ) = ( 2x + 1 ) m.

\leadstoArea of reactangular plot = l × b

\leadsto( 2x + 1 ) × x = ( 2x² + x ) sq.m.

\rule{300}3

  • Given: area of plot = 528 sq.m.

\leadsto2x² + x = 528

\leadsto2x² + x - 528 = 0

\rule{300}3

  • Required quadratic equation :–

\mapsto2x² + x - 528 = 0

\mapsto2x² + 33x - 32x - 528 = 0

\mapstox( 2x + 33 ) - 16( 2x + 33 ) = 0

\mapsto( 2x + 33 ) ( x - 16 ) = 0

\mapstox - 16 = 0 or 2x + 33 = 0

\mapstox = 16 or x = -33/2 \large{\pink{\underline{\tt{(Impossible)}}}}

\rule{300}3

Hence, Length of plot is 2x + 1

\rightarrow2 × 16 + 1 = \large{\green{\underline{\tt{ 33m}}}}

and breadth = \large{\blue{\underline{\tt{16m}}}}.

\rule{300}3

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