Question

area of a
regular Pentago
12​

Answer 1

Answer:

247.75

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Answer 2

Answer: area= 2.64

Step-by-step explanation:

A, area = 12

Using formula:

A= 1/4 $\sqrt[]{5(5+2\sqrt[]{5} } ) a^{2}$

Solving for a:

a= 2.5$^{3/4}$ $\sqrt{A}$/$\sqrt[]{5( \sqrt{20+5)^{1/4} } }$ = 2.5$^{3/4}$ .$\sqrt{12}$/ 5 .($\sqrt{20+5} ^{1/4}$) = 2.64099