Question

Area of a rhombus is 63 square cm. If the length of one of the diagonals is 9 cm, find the length of the other diagonal​

Answer 1

Step-by-step explanation:

1 Area of a rhombus-Product of its diagonals 2

1 Area of a rhombus= x d₁ × d₂ where d₁ = 30cm 2

1 2 → 150 = × 30 × d₂

d₂ = 2 x 150/ 30 = 10cm

..the other diagonal= 10cm

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Answer 2

Given :-

• Area of a rhombus is 63 square cm².
• The length of the diagonal s is 9 cm

To Find :-

• The length of the other diagonals.

Understanding Rhombus :-

A Rhombus is a polygon which have 4 equal side's The opposite sides are parallel to each other .

$\sf \: perimeter = 4a(a = 1 \: sides) \\ \sf \: area = \frac{1}{2} \times d {}^{1} \times d {}^{2} \\ \sf \: side(a) = \frac{1}{2} \sqrt{d {1}^{2} + d2 {}^{2} }$

•Calculate the other diagonal :-

• Let's the diagonal 2 be 'x' .

$\\ \sf\ = \frac{1}{2} \times d {}^{1} \times d {}^{2} \\ = \sf \: \frac{1}{2} \times 9 \times (x) = 63 \\ = \sf \: 1 \times 4.5 \times (x) = 63 \\ = \sf \: 4.5x = 63 \\ = \sf \: x = \frac{63}{4.5 } \\ = x = 14$

Hence, the other diagonal is 14 cm.

Verification ✓ :-

$\\ \sf \: area \: = \frac{1}{2} \times d {}^{1} \times d {}^{2} \\ = \sf \: \frac{1}{2} \times 9 \times 14 \\ = 1 \times 4.5 \times 14 \\ = 63 \sf \: (hence \: verified)$

•More Formulaes :-

•Area of a square = a²

•Area of a rectangle = length×Breadth

•Area of a Rhombus = 1/2 ×d¹×d²

•Area of s parallelogram =Breadth×height

•Area of a trapezium =

1/2× (sum of all parallel sides)×(height)

•Area of a Circle = πr²

•Area of a Semi circle = 1/2 πr²

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