area of a rhombus is 96 sa.cm .one
diagonals is 12 cm find the length of its
side
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Answer:
10cm
Step-by-step explanation:
Given measurement of one of the diagonals
= 12cm
Given area = 96cm²
Other diagonal = (2 × 96cm²) ÷ 12cm = 16cm
Now , imagine that the diagonals are bisecting each other . This will create 4 line segments from the centre point .
So , half of the diagonals will become two sides of a triangle ( ∵ The diagonals of a rhombus divide it into 4 congruent triangles . )
So , sides of the triangle = 6cm , 8cm and x
According to the Pythagoras theorem ,
x² = 6² + 8²
⟹ x² = 36 + 64
⟹ x² = 100
⟹ x = √100
⟹ x = 10
∴ The length of the sides of the rhombus is 10cm each .
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