Area of a right-angled triangle is 21 bc square centimetre. If the area is
equal to 15 sq. cm, and b=5, then find c.
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Answer:
Area of the triangle = √34 a² square units
= √34 × 12 × 12
= 36√3 cm²
= 36 × 1.732 cm²
= 62.28 cm²
Height of the triangle = √32 a units
= √32 × 12 cm
= 1.73 × 6 cm
= 10.38 cm
AB² = AC² - BC²
= 15² - 12²
= 225 - 144
= 81
Therefore, AB = 9
Therefore, area of the triangle = ¹/₂ × base × height
= ¹/₂ × 12 × 9
= 54 cm²
3. The base and height of the triangle are in the ratio 3 : 2. If the area of the triangle is 243 cm² find the base and height of the triangle.
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