Area of a right angled triangle is 300sq.m.If base is 15m,find the
perpendicular to the base.
Answers
Answer:
Length of the rectangle is 5.2 cm.
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.Area of a rectangle = l × b
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.Area of a rectangle = l × b= 2.1 m × 1.5 m = 3.15 sq m
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.Area of a rectangle = l × b= 2.1 m × 1.5 m = 3.15 sq m∴ The area of the rectangle is 3.15 sq m.
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.Area of a rectangle = l × b= 2.1 m × 1.5 m = 3.15 sq m∴ The area of the rectangle is 3.15 sq m.(3) Length of the rectangle is 3.5 m.
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.Area of a rectangle = l × b= 2.1 m × 1.5 m = 3.15 sq m∴ The area of the rectangle is 3.15 sq m.(3) Length of the rectangle is 3.5 m.Breadth of the rectangle is 1.2 m.
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.Area of a rectangle = l × b= 2.1 m × 1.5 m = 3.15 sq m∴ The area of the rectangle is 3.15 sq m.(3) Length of the rectangle is 3.5 m.Breadth of the rectangle is 1.2 m.Area of a rectangle = l × b
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.Area of a rectangle = l × b= 2.1 m × 1.5 m = 3.15 sq m∴ The area of the rectangle is 3.15 sq m.(3) Length of the rectangle is 3.5 m.Breadth of the rectangle is 1.2 m.Area of a rectangle = l × b= 3.5 m × 1.2 m = 4.2 sq m
Length of the rectangle is 5.2 cm.Breadth of the rectangle is 2.5 cm.Area of a rectangle = l × b= 5.2 cm × 2.5 cm = 13 sq cm∴ The area of the rectangle is 13 sq cm.(2) Length of the rectangle is 2.1 m.Breadth of the rectangle is 1.5 m.Area of a rectangle = l × b= 2.1 m × 1.5 m = 3.15 sq m∴ The area of the rectangle is 3.15 sq m.(3) Length of the rectangle is 3.5 m.Breadth of the rectangle is 1.2 m.Area of a rectangle = l × b= 3.5 m × 1.2 m = 4.2 sq m∴ The area of the rectangle is 4.2 sq m.
Answer:−
Perimeter of an isosceles triangle = 90 cm
\mathfrak{\large{\underline{\underline{Explanation:-}}}}Explanation:−
Given :- Area of an isosceles triangle is 300 cm². Height of the isosceles triangle is 15 cm
To find :- Perimeter of the triangle
Solution :-
Height of an isosceles triangle = 15 cm
First find base of the triangle.
Let the base of an isosceles triangle be x
\boxed{\sf{Area\:of\:the\:triangle= \dfrac{1}{2} \times Base \times Height}}Areaofthetriangle=21×Base×Height
Area of an isoceles triangle = 300 cm²
Equation formed :
\dfrac{1}{2} \times x \times15 = 30021×x×15=300
\dfrac{15x}{2} = 300215x=300
15x=300 \times 215x=300×2
15x = 60015x=600
x = \dfrac{600}{15}x=15600
x = 40x=40
Base of an isosceles triangle = 40 cm
Now refer to the attachment.
Consider Δ ABD
It has one the angle as 90° [Altitude]
Therefore Δ ABD is right angled triangle.
Base = x/2 = 40/2 = 20 cm (Since height of a right angle triangle triangle divides it into two congruent isosceles triangles by RHS congruency and AD = AC)
Height = 15 cm
Hypotenue = ?
Let the hypotenuse be y
In right angled triangle
By Pythagoras thereom
\boxed{\sf{Height^2 + Base^2 = Hypotenuse^2}}Height2+Base2=Hypotenuse2
Equation formed :
{15}^{2} + {20}^{2} = {y}^{2}152+202=y2
225 + 400 = {y}^{2}225+400=y2
625 = {y}^{2}625=y2
\sqrt{625} = y625=y
y = 25y=25
So, Hypotenuse = 25 cm
Now Consider Δ ABC
Two equal sides of an isosceles triangle = 25 cm
Base = 40 cm
Perimeter of a triangle = Sum of all sides
Perimeter of an isosceles triangle = 40 + 25 + 25 = 65 + 25 = 90 cm
So perimeter of an isosceles triangle = 90 cm