Question

area of a right angled triangle is 40 times it base .what will be the hieght​

Answer 1

Answer :-

Height of right angled triangle = 80 units.

Explanation :-

Given : Area of a right angled triangle is 40 times it base.

To Find : Height of the triangle.

Solution :

Let the base be x.

So, Area of triangle = 40x.

We know that,

Area of Triangle = ½ × base × height.

According to the Question,

➞ ½ × x × h = 40x.

➞ (x)(h) = (40x) × (2).

➞ (x)(h) = 80x.

➞ h = 80x/x

➞ h = 80.

Therefore, Height of Triangle = 80 units.

Answer 2

Question :

Area of right angled triangle is 40 times its base. What will be the height?

Given :

• Area of right angled triangle is 40 times its base.

To find :

• Height of the triangle.

Solution :

• Let the base of triangle be x.
• Area of triangle = 40x
• Let height = h

$\boxed{\underline{\tt Area \: of \: Triangle \: = \: \dfrac {1}{2} \times base \times Height }}$

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$\implies \tt { 40x = \dfrac {1}{2} \times {x} \times {h} }$

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$\implies \tt { 40x \times {2} = h \times x}$

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$\implies \tt {\dfrac {80x}{x} = h }$

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$\implies \tt {80 = h }$

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$\boxed {\tt Height \: of \: the \: right \: angled \: triangle \: = 80 \: units }$

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