area of a right triangle is 24 cm square and the square of the sum of the perpendicular sides is 196. Find the lengths of sides of the triangle
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Answer:
8 cm & 6 cm
Explanation:
Let the sides are 'a' and 'b'. (a>b)
Square of sum of the perpendicular sides is 196.
=> (a + b)² = 196
=> a + b = √196 = 14
=> b = 14 - a ... (1)
Area = 24 cm²
=> 1/2 *height * base = 24 cm²
=> 1/2 *a * b = 24
=> ab = 48
=> a(14 - a) = 48 {from (1)}
=> 14a - a² = 48
=> a² - 14a + 48 = 0
=> a² - 8a - 6a + 48 = 0
=> (a - 8)(a - 6) = 0
=> a = 8 & a = 6,
Take a = 8, as we took a>b, if a = 6 then b = 14-6=8 which is greater than 6.
So a = 8 then b = 14 - 8 = 6
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