Question

area of a right triangle is 24 cm2 and the square of sum of the perpendicular sides is 196 taking the perpendicular sides as x meter,and y meter

a) what the number is x+y?
b)find the number x-y?
c)find the length of sides of a rectangle ​

Answer 1

Step-by-step explanation:

length = 12.5 m, breadth - 8 dm.

ANSWER:

(i) Length = 24.5 m

Breadth = 18 m

∴ Area of the rectangle = Length × Breadth

= 24.5 m × 18 m

= 441 m2

(ii) Length = 12.5 m

Breadth = 8 dm = (8 × 10) = 80 cm = 0.8 m [since 1 dm = 10 cm and 1 m = 100 cm]

∴ Area of the rectangle = Length × Breadth

= 12.5 m × 0.8 m

= 10 m

Answer 2

Answer:

x = 8 y = 6

Step-by-step explanation:

• area of triangle = 1/2xy (half xy)
• square of sum of= (x+y)^2 (x+y the

both sides whole square)

___________________________

A) square of sum of = (x+y)^2 =196

both side

therefor,to find x+y we want to find root of 196

root of 196 = 14

• So x+y = 14

B) 1/2xy is aplicable to (x-y)^2 =(x+y)^2-4xy

• (x-y)^2 =(x+y)^2 - 4xy

= 196 - 4 × xy

we have 1/2xy.so we want to convert it

into xy.so we multiply with 2.

so we get xy = 48

• 196 - 4 × 48
• 196 - 192

(x+y)^2 = 4

x+y = root of 4= 2 so,x-y = 2

so we get

• x+y = 14
• x-y = 2

C) FOR X FOR Y

x + y = 14 (14 - 2)÷2

x - y = 2 = 6

_________

x = (14+2)÷2

= 8

LENGTH OF SIDE X = 8

LENGTH OF SIDE Y = 6

________THANK YOU________

FROM : Yadu