Question

area of a sector of a.circle with radius 6cm and angle of the sector 60 degree is​

Answer 1

Answer:

formula for area of sector=(theta/360)×πr²

                                         =( 60/360)×π×6²

                                         =(1/6)×π×36

                                          =6×π

                                          =(6×22)÷7=18.849cm²(approx)

Step-by-step explanation:

Answer 2

Answer:

$\boxed{area=132/7cm^2}$

Step-by-step explanation:

$\boxed{Tofind}$

area of the sector of the circle

$\boxed{answer}$

$\boxed{formula}$

$\frac{theta}{360} \times \pi \: r {}^{2}$

radius of the circle =6cm

theta=60degree

$area = \frac{60}{360} \times \frac{22}{7} \times 6 cm\times 6cm$

$area = \frac{132}{7} cm {}^{2}$