Question

Area of a square having perimeter equal to that of a rectangle having sides 10 cm and 6 cm will be

Answer 1

Answer:

Area of square will be= 64 sq-cm

Explanation:

Perimeter of square is equal to the perimeter of rectangle having sides 10 cm and 6 cm

Perimeter of rectangle having length l and breadth b

= 2(l+b)

= 2(10+6)

=2×16

=32 cm

Perimeter of square = 32 cm

We know that perimeter of square having each side a is given by = 4a

So,

4a= 32

a=8 cm

Area of square = side × side

= 8×8

= 64 sq-cm

Hope it helps you.

Answer 2

Answer:

Perimeter of rectangle: 10 + 10 +6 +6 =32 which also equals perimeter of square. 4s = perimeter of square: 32 = 4s. s = 32/4 = 8 cm.