Question

Area of a square is 4 sq. M more than 2/3 of the area of a rectangle. If the area of square is 64 sq. M, then find the dimensions of rectangle, given that breadth is 2/5 of length.

Answer 1

let L and B be the length and breadth of the rectangle resp.
area of the square =A=64sqm
and
B=2L/5
now acc. to the question..
A=2/3(area of rectangle)+4
64=2LB/3
64*3=2LB
64*3=2L*2L/5
64*3*5=4L^2
16*3*5=L^2
L=4\/15m
B=2L/5=2*4\/15/5=(8\/15)/5

hope this helps:p

Answer 2

Answer:

ACCORDING TO QUESTION:

AREA OF A SQUARE = 4+2/3*AREA OF THE RECTANGLE

LET THE AREA OF RECTANGLE BE x

Now substituting the values:-

64=4+2/3*x

64-4=2/3*x

60=2/3*x

x=60*3/2

x=90

90 IS THE AREA OF THE RECTANGLE

NOW:-

LET THE LENGTH BE x

Breadth=2/5x

AREA=LENGTH*BREADTH

90=x*2/5x

90=2/5*x^2(x to the power 2)

x^2=90*5/2

x^2=225

x=underoot of 225

x=15

BREADTH=2/5*15

=6

HOPE IT HELPS YOU

PLZ MARK AS BRAINLIEST

Step-by-step explanation: