area of a square is numerically less than twice its diagonal by 2. find the perimeter
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area of square=2d-2
1/2×d×d=2d-2. {here are of square is taken
d²/2=2d-2. as 1/2×product of
d²=4d-4s. diagonals}
d²-4d+4=0
d²-2d-2d+4=0
d(d-2)-2(d-2)=0
(d-2)(d-2)=0
d-2=0. d-2=0
d=2. . d=2
so diagonal d is 2 and side=√diagonal=√2
perimeter =4× side
=4×√2=4√2
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1/2×d×d=2d-2. {here are of square is taken
d²/2=2d-2. as 1/2×product of
d²=4d-4s. diagonals}
d²-4d+4=0
d²-2d-2d+4=0
d(d-2)-2(d-2)=0
(d-2)(d-2)=0
d-2=0. d-2=0
d=2. . d=2
so diagonal d is 2 and side=√diagonal=√2
perimeter =4× side
=4×√2=4√2
plz mark as brainliest
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