Question

Area of a square is twice the area of a circle. If the side of the square is 4
$\sqrt{77}$
m. then find the

radius of the circle?
​

Answer 1

$area \: of \: circle = \pi {r}^{2} \\ given \: side \: of \: square = 4 \sqrt{77} \: m \\ so \: area = ({4 \sqrt{77}) }^{2} = 1232 \: sq \: m\\ \\ according \: to \: question \\ 2\pi {r}^{2} = 1232 \\ = > {r}^{2} = \frac{1232}{2 \times 3.141} \\ (assume \: \pi = 3.141) \\ = > r = \sqrt{ \frac{1232}{2 \times 3.141} } = 14.0041 \: sq \: m \\ which \: is \: nearly \: equal \: to \: 14 \: sq \: m$