Area of a tniangle with vertices (k,0). (1,1) and (0,3) is 5 unit. Find the
value (s) of k.
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Answer:
area of triangle = 1/2| x1 (y2-y3)+ x2( y3 - y1) + x3 (y1 - y2)
1/2| k (1-3) + 1 (3-0) + 0 (0-1)| = 5
k - 3k + 3 = 10
-2k = 7
k = -7/2
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