Question

Area of a trapezium is 10500 cm². One of its parallel sides is longer than the other by 6cm
and height is 1m. Find its two parallel sides.​

Answer 1

Answer:

area of trapezium = 1/2 sum of parallel side •hieght

Step-by-step explanation:

1. 1/2(a+a+6).100=10500 , (a+3). 100=10500, 100a+300=10500 , 100a=10200, a=102 , one side=102 , other side= 102+6=108

Answer 2

$\huge{\underline{\underline{\bf{\red{Given}}}}}$

Area of trapezium = 10500cm² = 1.05m²

Height = 1m

$\huge{\underline{\underline{\bf{\red{Solution}}}}}$

Let the one parallel side be x then other side be (x+6)

$\implies\sf \frac{1}{2}\;(x+0.06+x)×1\;=\;1.05$

$\implies\sf (2x+0.06)1\;=\;1.05$

$\implies\sf 2x+0.06\;=\;2.1$

$\implies\sf 2x\;=\;2.1-0.06$

$\implies\sf x\;=\frac{2.04}{2}$

$\implies\sf x\;=\;1.02m$

first parallel side = 1.02m

second parallel side = 6 + 1.02 = 7.02m

$\large\underline\bold\purple{Note:-}$

$\large\sf Area\;of\;trapezium$

$\large\sf \frac{1}{2}×(sum\;of\;parallel\;sides)×height$