Area of a trapezium is 160 sq. cm Lengths of parallel sides are in the ratio 1:3.if smaller of the parallel sides is 18 cm in length, then find the perpendicular distance between them
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Answer=
Given,
Area of trapezium =160 m
2
The ratio of the length of its parallel sides =1:3
Smaller parallel sides =10 cm
∴ Length of greater side =10×3=30 cm
Let the distance between them =h
We know that,
Area =
2
1
× sum of parallel sides × height
⇒160=
2
1
(30+10)h
⇒160×2=40h
⇒h=
40
320
=8 cm
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