Question

area of a trapezium is 270cm square and its height is 12cm.if one of the parallel sides is longer than the other by 5cm, find the length of the two parallel sides

Answer 1

Let one of the sides be x... Then the other side =x+5
Given height =12 cm
Area of trapezium =1/2*(sum of parallel sides) *h
270=1/2*(x+x+5)*12
270=1/2*(2x+5)*12
270=(2x+5/2)*12
270=24x+60/2
270*2=48x+60
48x=540-60
48x=480
x=10
First side =10 cm
Second side=15cm

Answer 2

✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿

Answer:

The two parallel sides are 20cm and 25cm.

✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿

Step-by-step explanation:

Given:

Area of Trapezium = 270cm²

Height = 12cm²

Let one of the parallel sides be x.

parallel side 1 = x

parallel side 2 = x+5

✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿

To Find:

The length of the parallel sides :

Formula for Area of Trapezium = $\frac{1}{2}$ x height x (Parallel side1 + Parallel side2)

✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿

270cm² = $\frac{1}{2}$ x 12 x ( x +x+ 5 )

270cm² = 6 x (2x + 5)

$\frac{270}{6}$ = 2x+5

45 = 2x+5

45 - 5 = 2x

40 = 2x

$\frac{40}{2}$ = x

∴ 20 = x

Since the question says that one of the parallel sides is longer than the other by 5cm.

20 + 5 = 25cm

✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿

Solution:

Therefore, the length of the two parallel sides are 20cm and 25cm respectively.

✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿ ... ✿°•∘ɷ∘•°✿

╔═══════ ೋღ ღೋ ═══════╗

   ღ Hope this answer helps ya..

  ღ If this answer did help please mark as

      Brainliest and thank this answer.

  ღ Also rate this answer 5 stars.

╚═══════ ೋღ ღೋ ═══════╝