area of a Trapezium is 276 CM square and its height is 24 cm if one of the side is 7 cm longer than the other find length of both the parallel side
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area of trapezium=2(height)(sum of parallel sides)
let 1side be x
2nd side is x+7
so
2(24)(x+x+7)=276
24(2x+7)=276\2
2x+7=188\24
2x=47\6
x=47\12
x=3.9
y=10.9
let 1side be x
2nd side is x+7
so
2(24)(x+x+7)=276
24(2x+7)=276\2
2x+7=188\24
2x=47\6
x=47\12
x=3.9
y=10.9
Answered by
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☜☆☞hey friend!!! ☜☆☞
here is your answer ☞
→_→→_→→_→→_→→_→
Area of Trapezium A=1/2(Sum of parallel sides) × height(h)
Let one parallel side=a
Other side is a+7
A=276cm2
h=24cm
Hence A=276=1/2(a+a+7)×24
a=8 ______ answer
Hence
parallel sides of trapezium are 8cm and 15cm
hope it will help you
Devil_king ▄︻̷̿┻̿═━一
here is your answer ☞
→_→→_→→_→→_→→_→
Area of Trapezium A=1/2(Sum of parallel sides) × height(h)
Let one parallel side=a
Other side is a+7
A=276cm2
h=24cm
Hence A=276=1/2(a+a+7)×24
a=8 ______ answer
Hence
parallel sides of trapezium are 8cm and 15cm
hope it will help you
Devil_king ▄︻̷̿┻̿═━一
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